Wow, that’s impressive! I’m definitely downloading. I think I’ve came across this corpus, but thought it would be too large to process. The corpus I’m…
I think he measured the distances between recurring bigrams, and then looked for factors in those distances that occur more often than expected. It’s…
"IofC" is easy, it’s Index of Coincidence (IC or IoC). But I can’t quite understand the rest. Especially the part about "numbers" …
It’s an interesting idea, but what exactly does using 4/5/6-grams in parallel accomplish? I must’ve missed an important key point in the discussion. :…
It’s an interesting idea, but what exactly does using 4/5/6-grams in parallel accomplish? I must’ve missed an important key point in the discussion. :…
I’m getting a stable solve for both ciphers as well using my own solver, but with a pretty low overall score, which means the recovered plaintext isn’…
Thanks for running the experiment! Seems to suggest it was done on purpose, considering only 1 in 35 chance of it happening, well, by chance. 🙂 Altho…
Hmm, yes, perhaps there is a standard way of building the key for a homophonic substitution cipher described in one of the books, that has this proper…
It’s a curious find indeed! It makes sense that all of the letters end in E because E maps to itself. So it in a sense short-circuits any further link…
Right off the bat, you have a "C" that translates to dash and then to a dot elsewhere. Similarly stands for a dot at the start of the ciphe…
Hows your solver coming along? Any plans for a release or working on a GPU version? So, I’ve finally implemented an OpenCL version of my solver runn…
I might have to officially give up. Know when to hold ’em, know when to fold ’em, as they say. 🙂 I don’t think I’ll be able to solve it without hints…
Not wrapping around the cipher it might be as rare as 1 in a million (versus 340 randomized) and we didn’t have to search through millions of variatio…
Simple Proposed Cipher: 1. Zodiac drafted the plaintext horizontally and there were slightly more than 323 symbols. The resulting number of rows is 1…
Daikon what is your thought on the bigram peak a period 19 or 15 mirrored? Not wrapping around the cipher it might be as rare as 1 in a million (versu…