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(@wpackwood)
Posts: 6
Active Member
Topic starter
 

Hi All

I’m new to this site and relatively new to the Zodiac.

Is anyone aware of any part of the 340 Cipher ever being decoded?

Thanks

 
Posted : May 9, 2019 9:11 pm
traveller1st
(@traveller1st)
Posts: 3583
Member Moderator
 

HI wpackwood,

Welcome to the forum and in short the answer, I believe, no. The cipher guys may expand on it but there have been many ‘parts’ that have been suggested as being deciphered but unless we can find an enciphered scheme that ‘makes sense’ or ‘works’ then people will continue to find ‘parts’ that they feel must be a clew[sic] or a partial solution.

trav.


I don’t know Chief, he’s very smart or very dumb.

 
Posted : May 9, 2019 9:54 pm
(@themist)
Posts: 162
Estimable Member
 

There are tons of proposed partial solutions out there, but I have never seen one that gives acceptable plaintext for the whole cypher.

 
Posted : May 10, 2019 3:44 am
Quicktrader
(@quicktrader)
Posts: 2598
Famed Member
 

Assuming the ciper to be a homophone substitution cipher, it is very easy to solve it. It just takes a very fast computer..

+ symbol occurs >7%, thus frequent letter (ETAOINSRHDL…)

++ occurs three times, thus frequent double letter (EE, SS, LL, TT, PP, MM, OO, NN, RR, GG, DD, FF..)

Leaves ETORNSL..

With E and T having too many homophones so three double letters could even occur, and the rest not being compliant with letter OR double letter frequencies expected (Bernoulli), the + symbol represents the letter ‘S’.

So, yes. If there is no statistical outlier etc..if if if..

Search for ‘340 – partially solved’ if interested.

QT

*ZODIACHRONOLOGY*

 
Posted : May 11, 2019 10:23 pm
(@wpackwood)
Posts: 6
Active Member
Topic starter
 

The 340 is broken into 3-Parts

• Main Message
• Zodiac’s initials
• Layer2 of testing potential future words/phrases

Both the 340 & 480 were able to be deciphered as the author made the error of using the word BECAUSE in identical sections in the 340 & 480

480 BECAUSE starts at section 2/line 1 (B = 3rd character ‘K’) (*Section2 = Page2)
340 BECAUSE starts at section2/ line 1 (B = 7th character ‘O’) *The 1st character on this line is the last character in section1 and not to be counted.

*Donald. G. Harden’s 480 translation is incorrect and the last 18 characters of this cipher that have never been translated are: –
• AND CUT HER THROAT. DGH

The reason I chose to locate BECAUSE is that it was used frequently by the Zodiac in his handwritten letters.

The Bus Bomb Letter
The Belli Letter
My Name Is letter
Kathleen Johns Letter,
LA Times Letter

Therefore, a high probability it would have been used in his ciphers.
*A statement followed by a reason with BECAUSE in the middle.

From locating BECAUSE I was confident there was structure but pointless to second guess what he may have written prior and beyond this word as BECAUSE had to be explained for the remainder of the ciphers to be successfully translated.
Eventually after 6 months from looking into the ciphers I located all his alphabets which then determined the frequency and order of alphabets.

Main Message – 340
IAC WILL KILL AGAIN STINE WAS SO EASY HE NEVER KNEW WHAT HIT HIM POOR GUY WAS ALIVE
ONE DAY DEAD THE NEXT I DON’T MIND IF IM SEEN OR CAUGHT OR IF PIGS DO KILL ME BECAUSE
I FANTASIZE DYING SHOOTING PIGS REBORN IN PARADICE SLAVES I CALL START TO SING I NEVER
STOP PREACHING NEVER STOP TALKING A GIRL SCREAMS AS I TORTURE HER LAUGHING I FORCE
PINE SPLINTERS UNDER HER NAILS AND BURN THEM UNTIL SHE SCREAMS ALOT LOUDER THE ZOD

The 340 is broken into three sections. They start at the following:
• Section1 = Line 1/ character 15 (G)
• Section2 = Line 8 character 2 (G)
• Section3 = Line 16 character 16 (G)

To obtain the alphabets you complete the following steps.

• Write a standard alphabet (Excluding Q)
• Starting at each section with G write only letters as they appear in order. With each letter darken that letter to the above alphabet.
o *Any letter that is duplicated, that letter falls to a lower level until you have reached the end of the Section letters. Repeat process for section 2&3. Once complete you will have 3 main alphabets with further variations as you make your way down the cipher: –

Section1
1. A B C D E F G H I J K L M N O P R S T U V W X Y Z
2. G N B O D W Y K M U Z L H J S V R I F P C X
3. A E Q T N Y Z J S P C X B W M R D U V L I O F K G

Section2
4. A B C D E F G H I J K L M N O P R S T U V W X Y Z
5. G J O N Y L M Z R F B A K U V E I D T S X C
6. H P W L A D S X C Y T G E Z J N V U K R I O M F B
7. B D F I K M O S U X Z A C E G J L N R T V Y
8. A C E G I K M O R T V X Z B D F H J L N P S U W Y
9. Z J N V U K R I O M F B H P W L A D S X C Y T G E
10. N O P R S T U V W X Y Z A B C D E F G H I J K L M

Section3
11. A B C D E F G H I J K L M N O P R S T U V W X Y Z
12. G R T L C F W B I P O S H Y M D N Z A K E V
13. J U X G B Y M D N Z A K E V F S R P C O H L T W I

*Letters and symbols can be off set up to the start of the above line.

In order to translate a letter/symbol that letter/symbol can be counted to the beginning of the line it appears or to the beginning of the line above. Letters/symbols can be counted as a combination or in their own group. i.e. only letters or only symbols or both but all counts will finish at the beginning of a line. For the 1st line in the 340, the count is offset from the last line.

For example: REBORN IN PARADICE (Section2/ Line10/ Starting character J)
J = R (Count all Letters & Symbols to this line using DARK letters from Alphabet5)
+ = E (Count symbols to the start of the line above using Alphabe5)
O = B (Count Letters to the start of the line above using Alphabe5)
9 = O(Count all Letters to the start of the line above using Alphabet7)
Triangle = R (Count all Symbols to this line using DARK letters from Alphabet5)
< = N (Count all Letters & Symbols to this line using DARK letters from Alphabet4)
F = I (Count Letters to the start of this line using Alphabet8)
B = N (Count all DARK Letters to the start of the line above using Alphabet4)
B’ward Y = P (Count all Letters & Symbols to this line using Alphabet4)
• ¬¬= A (Count all Letters & Symbols to this line using Alphabet9)
U = R (Count all Letters to the line above using Alphabet9)
+ = A (Count symbols to the start of this line using Alphabet8)
R = D (Count Letters to the start of this line using Alphabet7)
/ = I (Count Letters & Symbols to the start of this line using Alphabet7)
Dark Circle = C (Count Symbols to the start of this line using Alphabet4)
Upside-down T = E (Count symbols to the start of the line above using Alphabe10)

Zodiac’s initials
The Zodiac placed his initials (DGH) at the end of the 480 and created his own monogram in Section1 of the 340 by placing his initials (DGH) against the Zodiac symbol.
Although the Zodiac ciphers are the first time, I have looked at translating a cipher I can see how he progressed in making the process more difficult to locate his identity from the 480 to the 340.

The 480, sending 3 parts to different locations…each part representing the start of a section and placing his initials at the end of letter where in the 340 merging 3 sections into one and offsetting the beginning of each section then hiding his initials.

I believe his arrogance shows in the 340 in that the sections could be interpreted as GO.GO. GO

I further believe his message was meant for one reason and that was to give his identity. Basically, laughing at everyone.

All the above information represents 3 possibilities: –
• The Zodiac shares the same initials as Donald.G.Harden
• Donald.G.Harden is the Zodiac
• My translations are incorrect. For my translations to be incorrect the author of the ciphers unknowingly created a coherent sub-message in both ciphers outside of his messages.

Layer2 of testing potential future words/phrases
Upon translating REBORN IN PARADICE I halted the 340 for 2 reasons: –
• I could see unique symbols in Section2 outline an abbreviated message ‘M C IN RIV’. I took this as Mennie Cops In Riverside’ Other words followed such as death, die, Triash, Deaf, Eve, Wimp. I initially thought it was a deliberate diversion intentionally planted by the author in order to make the reader lean towards a false conclusion as the translation was nearing completion but then ‘Trash – Misspelt Triash’ has lead me to conclude the author has 3 block templates and plays with words to see if they fit in allocated sections. For example: Dolnald.G.Harden translated ‘Reborn In Paradice’ in Section2 of the 480. As I understand it ‘Reborn In Paradice’ has never been communicated prior to the 480 translation. ‘Reborn In Paradice’ is not in the 480 but it does appear in the 380 in Section2 therefore if my translation is correct there are only 2 possibilities: –
• The Zodiac read the 480 translation in the paper and adapted the ‘Reborn In Paradice’ into the 340
• Donald.G.Harden was already working on his 340 cipher and allocated it to Section2.

My Name Is Cipher
The letters from ‘My Name Is’ are the offset letters to determine the 13-letter name.
Once these letters are highlighted against the alphabet you have the following: –

A B C D E F G H
The 1st Character (Zodiac symbol) = D (Count all letters and symbols using a normal alphabet)
The 2nd Character = G (Count all letters & symbols using only light letters from the alphabet)
The 4th Letter ‘K’ = H (Count all letters & symbols using only light letters from the alphabet)

*The other characters and letters have their assigned letter once all the other letters from the main cipher have been marked.

Ultimately if the authorities truly have the Zodiac’s DNA only testing from a family member will prove that however I believe so much time has passed this case will remain open forever regardless of what is presented.

 
Posted : July 8, 2019 12:26 am
jacob
(@jacob)
Posts: 1266
Noble Member
 

I’m a little speechless wpackwood, an impressive debut post to say the least.

 
Posted : July 8, 2019 12:36 am
Quicktrader
(@quicktrader)
Posts: 2598
Famed Member
 

Honestly I can’t see how this shall fit into the cipher’s structure.

Could you write your cleartext into it, please?

http://www.oranchak.com/zodiac/webtoy/#

IMO it simply doesn’t fit.

QT

*ZODIACHRONOLOGY*

 
Posted : July 8, 2019 1:25 am
(@themist)
Posts: 162
Estimable Member
 

Interesting, but I don’t understand your example. Could you give a character by character solution? Then we can properly evaluate it. Thanks.

 
Posted : July 8, 2019 7:13 am
(@wpackwood)
Posts: 6
Active Member
Topic starter
 

I’ll put a character by character for section1 over the next few days as this contains his monogram. after that if you want the other sections I’ll try to do asap as I work long hours…hope that’s ok.

When its posted I recommend you have a copy of the 340 with a pen & paper as it will show up better if you personally conduct the exercise.

I also recommend having page2 of the 480 handy as I’ll attemp to explain why BECAUSE is important.

thanks

 
Posted : July 8, 2019 11:05 pm
jacob
(@jacob)
Posts: 1266
Noble Member
 

Regarding your 480 solution, there is a DH from Riverside who went to school with Cheri Jo Bates. Middle initial is not a match, however. viewtopic.php?f=107&t=2403

 
Posted : July 8, 2019 11:40 pm
Quicktrader
(@quicktrader)
Posts: 2598
Famed Member
 

Before we get into details of ‘potential’ solutions, we should wait for it fitting e.g. into Webtoy. Nevertheless the word ‘because’ is interesting für combining both, word pattern & frequency.

QT

*ZODIACHRONOLOGY*

 
Posted : July 9, 2019 12:08 am
(@wpackwood)
Posts: 6
Active Member
Topic starter
 

Hi QT

Your statistical chart is based on frequency, so a repetitive symbol/letter will most likely be inline with the list of the most common letters in English language correct?

An example: – + should equal a vowel.

Zodiac encrypted his message with placement. So long as letters were used every symbol could be the + sign. The message would be the same.

For example. The symbol + in section2 represents A, E, I, R, S, Z

Line 9. Character 4 (+) = S
Alphabet: G J O N Y L M Z R F B A K U V E I D T S X C
You count all letters and symbols (Including this symbol) to the start of Section2 (G) – The line above this character….20 counts

Line 9. Character 6 (+) = Z
Alphabet: A B C D E F G I J K L M N O R S T U V X Y Z
You count all letters and symbols to the start of Section2 (G) – The line above this character…..22 counts

Q. How do we obtain these alphabets?
Write a standard alphabet on a peice of paper (Exclude Q)
Starting with the first letter (G) at section2 write that below the standard alphabet. Before moving to the next letter (J) darken the letter G in the alphabet above.
Any letter that reappears as you make your way down falls to a lower level and then you darken the letter above.

Complete this process with all the letters ubtil you reach the last letter of section2 (Line16 / Letter M)

You now have alphabet:-
G J O N Y L M Z R F B A K U V E I D T S X C

You also have a darkened alphabet: –
A B C D E F G I J K L M N O R S T U V X Y Z

Now you write all the light letters starting from the top making your way all the way down to the repetetive letters.
H P W L A D S X C Y T G E Z J N V U K R I O M F B

Thats how we obtain his alphabets.

Additionally, you have a square with a dot in the middle on your chart. Although this symbol is unique as one page there are many when you break the letter into its 3 parts. These letters are to pickout arreviated sub messages.

For example: Line8/ Character6 is a unique symbol. Alhough it is repeated on line5 it is a different section.
Line8/ Character6 symbol is part of a sub message (M C IN RIV) – Mennie Cops In Riverside.

Hope this makes sense.

Thanks

 
Posted : July 9, 2019 12:47 am
(@stitchmallone)
Posts: 798
Prominent Member
 

I’m no cipher or code genius at all and only know how to make Cesar ciphers and solve them. Would be cool if wpackwood would continue to post. Want to see what the code guys on here think of that solution and if it holds water.

 
Posted : July 11, 2019 10:21 am
AK Wilks
(@ak-wilks)
Posts: 1407
Noble Member
 

I’m no cipher or code genius at all and only know how to make Cesar ciphers and solve them. Would be cool if wpackwood would continue to post. Want to see what the code guys on here think of that solution and if it holds water.

I agree. But this should be posted in our cipher section. It will get more views and comments by interested members at that section. Move your post here: viewforum.php?f=81

MODERATOR

 
Posted : July 12, 2019 7:40 am
(@stitchmallone)
Posts: 798
Prominent Member
 

I’m no cipher or code genius at all and only know how to make Cesar ciphers and solve them. Would be cool if wpackwood would continue to post. Want to see what the code guys on here think of that solution and if it holds water.

I agree. But this should be posted in our cipher section. It will get more views and comments by interested members at that section. Move your post here: http://www.zodiackillersite.com/viewforum.php?f=81

I agree also for moving it.

 
Posted : July 13, 2019 12:04 am
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