It’s reasonable to assume the solution of the 340 requires a key.
It’s also reasonable to assume to key was given in the card.
"A thing" he can’t do with "it" (it removed from a thing) is "hang."
The pen is hanging in the card. Maybe hang is the key, or hanging or some iteration thereof. Or maybe it’s a clue that the cipher is a hangman cipher.
If hang is transposed over HER7 there is a 1:4:4:1 shift. If the cipher is a shift or Ceasar cipher it’s possible that the repeating pattern is 1:4:4:1.
It’s also possible that the cipher is first a substitution cipher, then requires a shift.
These are just observations. Let me know what you think or if anyone can apply these ideas to the 340.
Thanks.
Homophone substitution, if so, wouldn’t require any key.
QT
*ZODIACHRONOLOGY*
Right. My suggestion was that the plain text requires a substitution to be applied first, then that text could be solved by a shift and if so that key could be hang or 1:4:4:1. Again just a thought.
Right. My suggestion was that the plain text requires a substitution to be applied first, then that text could be solved by a shift and if so that key could be hang or 1:4:4:1. Again just a thought.
Hey Echoes,
You are suggesting vigenère at the plaintext level. That is statistically detectable even after homophonic substitution.
Here is such a cipher I just created, with a Zodiac plaintext, encoded with the keyword "hang" plus homophonic substitution:
Z7EH9XN.-MW)9]9PL SU%9=TV5C4^RS9K:B RYHP703!NF9_G>&(< ^#9HYEAJNK2,NKW., $''N+7'B6C4^GVNR0 O/'9!%<9TK12L#P5( %-E'NU-NGI,=DM&* YK49^N&%6$/V+ZT0G KX##HV358S%>E97:9 1GM&B*5O_K^AI0;G& NR#@'AW-NK4PN]RC O$J$'X19.E6H$WX27 WT+GI19U0VP5357> V!M5BAZ_O'"3500W= #H&B%>V!M5G]CK+$' [IZ-&M7W*$UT34N> 9=:6G]FNPY'Q?C(<9 TKN+7E"ZH'V.$NJ0I #N):8^X0'HO9%2-'W M5,MNL/W]L-';IRNU
Copy and paste it in my app (AZdecrypt Lite) @ http://jarlve.vdm-service.be in the cipher window and click on statistics, and select periodic index of coincidence. Note the higher sigmas for by columns at multiples of 4 since the keyword "hang" is 4 letters long.
Period 2, by columns: 3.54682 Period 3, by columns: 1.17876 Period 4, by columns: 7.96435 <--- Period 5, by columns: 0.25398 Period 6, by columns: 2.34660 Period 7, by columns: -0.28857 Period 8, by columns: 4.69689 <--- Period 9, by columns: 0.28062 Period 10, by columns: 1.11822 Period 11, by columns: 0.08812 Period 12, by columns: 5.50719 <--- Period 13, by columns: 2.75048 Period 14, by columns: 0.77875 Period 15, by columns: 0.34662 Period 16, by columns: 3.15241 <--- Period 17, by columns: -1.87464
The non browser version of AZdecrypt (in my signature) can solve vigenère + homophonic substitution and I have tested the 340 up to a key length of 13. I also feel that the statistics in the 340 do not point towards such a hypothesis.
And here is a screenshot from Largo’s Peek-a-boo with the basically the same thing but then visually. I colored the multiples of 4 with red myself. To be clear, this is from the "hang" keyword cipher.
Jarive–
Awesome! Thanks so much.
As a team we can always do more
I always feel dumb when I read this type of messages! ^^
That makes two of us
Jarive–
Awesome! Thanks so much.
As a team we can always do more
A more thorough investigation into vigenère still has to be done though as a bunch of nulls and/or skips could complicate the matter.
Jarlve–
So any four letter word will cause increases at every fourth column on the y axis of the bar graph?
Hi Echoes,
Let’s say the Vigenere keyword is "HANG", four letters long. This means that every fourth letter in the cipher is encrypted with the same alphabet. This is what makes these spikes.
EDIT:
Here is a good explanation: http://practicalcryptography.com/crypta … re-cipher/
Thank you!
Though even a single null or skip can easily break the pattern.
