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Route Transposition and Phenomenon

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(@largo)
Posts: 454
Honorable Member
 

I am glad that you like the font and that you have a use for it.

Largo, I adapted your wonderful fonts and combined them into a single font, and made each symbol a constant width, making it easier to display cipher texts in a grid format. I also drew in the missing symbols from Z13 and Z32, and moved the symbols around to match the webtoy transcription.

Thank you for making it a monospaced font, I’ve wanted to do that for a long time. I also like your idea to put all symbols in one font. Thank you for putting the font on your webpage!

 
Posted : November 13, 2017 2:17 pm
doranchak
(@doranchak)
Posts: 2614
Member Admin
 

For some reason I can’t get to the link that shows Moonrock’s different cycle types.

For some reason, he removed his posts. I wonder why. But here’s a reply from Jarlve that quotes Moonrock’s cycle types:
http://www.zodiackillersite.com/viewtop … 762#p50762

So what about this kind of cycle to explain things. Maybe he just used a pattern and if we can find it…

Interesting idea. In the first example, "DE" would still happen 4 times in a row ("AB" 4 times in the 2nd example) and so can still be detected by a L=4 search. But it could explain why higher-order cycles are not as easily found. Should be worth investigating.

http://zodiackillerciphers.com

 
Posted : November 13, 2017 2:30 pm
smokie treats
(@smokie-treats)
Posts: 1626
Noble Member
Topic starter
 

Yeah the font is really fantastic. The numbers as symbols throws people off I think and if I want to make a point about the 340 I think sometimes it diminishes that.

Moonrock wrote this:

1. The perfect cycle, which has substitutions arranged in an unchanging pattern throughout the entire cipher: 12345 – 12345 – 12345 – 12345.
2. The increasingly random cycle, which has substitutions start off in an organized cycle and gradually become random: 12345 – 12345 – 12435 – 24153.
3. The decreasingly random cycle, which is the opposite of the increasingly random cycle: 24153 – 12435 – 12345 – 12345.
4. The random cycle, which has the substitutions arranged in random order: 32415 – 12543 – 41352 – 53124.
5. The concurrent cycle, which has two separate cycles existing at the same time for a single substitution; 1 and 5 cycling, and 2, 3, and 4 cycling in the following example: 12345 – 21354 – 23154 – 23415.
6. The palindromic cycle, which has the substitutions arranged in an order that reads the same forward and backward: 11211 – 11211 – 11211, 12321 – 12321 – 12321, and 123454321.
7. The inverted cycle, which has a uniform cycle inverted to be the opposite of what it was beyond a certain point: 12345 – 12345 – 54321 – 54321, and 11211 – 11211 – 22122 – 22122. The former example is an example of a perfect cycle being inverted, which creates a palindrome, and the latter example is of a palindromic cycle being inverted.
8. The shortened cycle, which has a cycle decrease in length as the ciphertext progresses: 12345 – 12345 – 1234 – 1234 – 123 – 123.
9. The lengthened cycle, which is the opposite of the shortened cycle: 123 – 123 – 1234 – 1234 – 12345 – 12345.

10. The regional cycle, which restricts substitutions to or from specific regions, or areas, of the ciphertext; this restriction typically manifests as either a restriction to specific rows or to specific columns, and, if used exclusively, is the equivalent of a series of simple substitutions.
11. The semi-regional cycle, which has the frequency of substitutions fluctuate between different regions, or areas, of the ciphertext in a similar way to regional cycling. When regional and semi-regional cycles are combined, it increases their level of security. Both regional and semi-regional cycles are capable of being accompanied by non-regional assignment of substitutions.
12. The sequential cycle, which is when one type of cycle is followed by another type of cycle: 12345 – 12345 – 123454321 – 1234321 – 12321; in this example, a perfect cycle changes to a palindromic cycle, which is then shortened.

I thought about the shortened cycle and lengthened cycle when lying awake in the dark last night. I will consider exploring that. The 340 does have cycling in it, but maybe this is the answer to why there aren’t long cycles.

Jarlve, what do you think?

 
Posted : November 13, 2017 3:45 pm
doranchak
(@doranchak)
Posts: 2614
Member Admin
 

Smokie, your grid looks great with Largo’s font! I have a similar cipher-highlighting tool that I want to use with the new font. I love that the font works at any resolution, has a nice transparent background, and can be made any color.

Thank you for making it a monospaced font, I’ve wanted to do that for a long time. I also like your idea to put all symbols in one font. Thank you for putting the font on your webpage!

You’re welcome. Let me know if you spot any problems with it. I tried to be careful to not miss any symbols and to map to the actual cipher texts properly. There may be some lingering warnings/errors in the TTF file; I am not sure if they will cause any noticeable problems.

http://zodiackillerciphers.com

 
Posted : November 13, 2017 4:32 pm
smokie treats
(@smokie-treats)
Posts: 1626
Noble Member
Topic starter
 

8. The shortened cycle, which has a cycle decrease in length as the ciphertext progresses: 12345 – 12345 – 1234 – 1234 – 123 – 123.
9. The lengthened cycle, which is the opposite of the shortened cycle: 123 – 123 – 1234 – 1234 – 12345 – 12345.

I will make some of these for testing soon.

 
Posted : November 13, 2017 5:56 pm
Jarlve
(@jarlve)
Posts: 2547
Famed Member
 

Jarlve, what do you think?

Go for it.

I did a follow up on your caesar shift by thirds hypothesis and it actually decreases unigram distance on average. The sigma of the unigram distance observation went up from 2.32 to about 3.20 (depending on the shifts used).

AZdecrypt

 
Posted : November 13, 2017 9:12 pm
Jarlve
(@jarlve)
Posts: 2547
Famed Member
 

At what period did I encode this remarkable cipher?

[A[Z.Z[A:6O2?.?:
-G-@M,!-6&6!0F,@
4=3O6&60FH%-=31J4
M1Z6::51275:9^K+-
51J]-=H%CL0JGL@K,
0L+K1[0J]L+H/J9KP
^LCH3/KP5+':H='SS
JRZ5SS/RYW)]5P^^X
DW/YW)]WYR<))]%XS
VXP^W*?$C$P@$X)X<
$D$PG$TT"CT;'(^"T
TX(^>R3QQB@Z<B==7
NT;'^N%V_;"G"<_?'
Q_B=N_[<_;'_7;"(N
9N8N7#VVG8Q8GBQ(#
(?IQI9#@8I(9IVV_;
8#4IDEZ#UUE97#UUG
E@BYEY><UIDE<#7#U
U(B_2#DE>B3Y>OIFE
GE@M3!.>,7[UA&%>

AZdecrypt

 
Posted : November 13, 2017 10:35 pm
smokie treats
(@smokie-treats)
Posts: 1626
Noble Member
Topic starter
 

Here is one with decreasing cycles.

A 1 2 3 4 1 2 3 1 2 1 2 3 4 1 2 3 1 2 1 2 3 4 1 2 3 1 2 1 2 3 4
B 5 6 5 6 5 6 5 6 5 6 5 6 5
C 7 8 7 8 7 8 7 8 7 8 7
D 9 10 9 10 9 10 9 10 9 10 9 10 9 10 9
E 11 12 13 14 11 12 13 11 12 11 12 13 14 11 12 13 11 12 11 12 13 14 11 12 13 11 12 11 12 13 14 11 12 13 11 12 11 12
F 15 16 15 16 15 16 15 16 15 16
G 17 18 17 18 17 18 17 18
H 19 20 21 22 19 20 21 19 20 19 20 21 22 19 20 21 19 20
I 23 24 25 26 23 24 25 23 24 23 24 25 26 23 24 25
J
K 27
L 28 29 28 29 28 29 28 29 28 29
M 30 31 30 31 30 31 30 31
N 32 33 34 35 32 33 34 32 33 32 33 34 35 32 33 34 32 33 32 33 34 35 32
O 36 37 38 39 36 37 38 36 37 36 37 38 39 36 37 38 36 37 36 37 38 39 36 37 38 36 37 36 37 38 39 36 37 38 36 37
P 40 41 40 41 40 41
Q 42
R 43 44 45 46 43 44 45 43 44 43 44 45 46 43 44 45 43 44 43
S 47 48 49 50 47 48 49 47 48 47 48 49 50 47 48 49 47
T 35 36 37 38 35 36 37 35 36 35 36 37 38 35 36 37 35 36 35 36 37 38 35 36 37 35 36 35 36 37 38 35 36 37 35
U 55 56 55 56 55 56 55 56
V 57 58 57 58
W 59 60 59 60 59 60 59 60
X
Y 61 62 61 62
Z

15 36 19 5 9 23 20 57 28 1 37 35 36 7 38 10 37
38 39 24 25 35 11 12 40 47 48 13 2 9 27 21 14 3
32 16 59 36 30 15 43 22 6 10 29 19 37 44 8 4 11
12 45 33 17 38 36 1 13 36 49 11 2 26 3 12 55 61
11 34 12 16 5 35 23 37 37 18 1 20 35 46 6 32 7
2 36 8 35 9 41 13 1 36 58 36 2 3 10 14 37 38
62 4 11 9 37 38 21 7 35 12 17 36 13 5 6 28 57
8 19 39 1 42 2 36 15 29 11 20 19 37 24 5 6 3
28 29 25 37 23 10 33 56 34 43 24 9 31 1 12 60 16
11 2 35 12 38 50 32 33 36 10 23 24 59 7 60 37 32
30 25 36 40 5 20 47 33 13 58 18 55 41 14 8 44 11
1 34 17 7 35 21 45 61 26 40 36 48 56 15 35 55 36
12 23 59 37 6 13 37 22 11 12 2 32 38 16 38 28 39
9 35 43 5 33 3 11 4 36 29 1 10 49 31 6 37 60
44 47 43 44 19 38 2 18 36 45 5 15 9 20 36 12 56
13 34 3 37 24 37 14 25 36 17 8 11 1 62 35 59 37
7 32 48 10 16 36 33 38 21 47 30 31 39 28 46 32 48
12 2 35 36 37 38 55 56 13 18 33 11 49 35 1 34 36
37 9 19 35 43 60 38 50 2 47 29 44 12 48 30 36 36
32 20 37 45 41 11 35 31 3 43 37 44 12 49 47 43 4

It is way too cyclic for L=2 because I went like this 1 2 3 4 1 2 3 1 2 1 2 3 4 instead of like this 1 2 3 4 1 2 3 1 2 1 1 2 3 4, but spreads out some of the symbols farther from each other.

 
Posted : November 13, 2017 10:42 pm
smokie treats
(@smokie-treats)
Posts: 1626
Noble Member
Topic starter
 

I messed up on the last one because letter T has symbols that are wrong.

Try this one maybe it will be better. Note that I changed the cycles a little bit. I went 1 2 3 4 1 2 3 1 2 1 1 2 3 4 so the 1 repeats and breaks up the L=2 cycle.

A 1 2 3 4 1 2 3 1 2 1 1 2 3 4 1 2 3 1 2 1 1 2 3 4 1 2 3 1 2 1 1
B 5 6 5 6 5 6 5 6 5 6 5 6 5
C 7 8 7 8 7 8 7 8 7 8 7
D 9 10 9 10 9 10 9 10 9 10 9 10 9 10 9
E 11 12 13 14 11 12 13 11 12 11 11 12 13 14 11 12 13 11 12 11 11 12 13 14 11 12 13 11 12 11 11 12 13 14 11 12 13 11
F 15 16 15 16 15 16 15 16 15 16
G 17 18 17 18 17 18 17 18
H 19 20 21 22 19 20 21 19 20 19 19 20 21 22 19 20 21 19
I 23 24 25 26 23 24 25 23 24 23 23 24 25 26 23 24
J
K 27
L 28 29 28 29 28 29 28 29 28 29
M 30 31 30 31 30 31 30 31
N 32 33 34 35 32 33 34 32 33 32 32 33 34 35 32 33 34 32 33 32 32 33 34
O 36 37 38 39 36 37 38 36 37 36 36 37 38 39 36 37 38 36 37 36 36 37 38 39 36 37 38 36 37 36 36 37 38 39 36 37
P 40 41 40 41 40 41
Q 42
R 43 44 45 46 43 44 45 43 44 43 43 44 45 46 43 44 45 43 44
S 47 48 49 50 47 48 49 47 48 47 47 48 49 50 47 48 49
T 51 52 53 54 51 52 53 51 52 51 51 52 53 54 51 52 53 51 52 51 51 52 53 54 51 52 53 51 52 51 51 50 50 50 50
U 55 56 55 56 55 56 55 56
V 57 58 57 58
W 59 60 59 60 59 60 59 60
X
Y 61 62 61 62
Z

15 36 19 5 9 23 20 57 28 1 37 51 52 7 38 10 53
54 39 24 25 51 11 12 40 47 48 13 2 9 27 21 14 3
32 16 59 36 30 15 43 22 6 10 29 19 37 44 8 4 11
12 45 33 17 38 36 1 13 52 49 11 2 26 3 12 55 61
11 34 11 16 5 35 23 37 53 18 1 20 51 46 6 32 7
2 52 8 51 9 41 12 1 36 58 51 1 2 10 13 52 53
62 3 14 9 36 37 21 7 54 11 17 51 12 5 6 28 57
8 19 38 4 42 1 39 15 29 13 20 19 52 24 5 6 2
28 29 25 36 23 10 33 56 34 43 24 9 31 3 11 60 16
12 1 53 11 37 50 32 33 38 10 23 23 59 7 60 36 32
30 24 51 40 5 19 47 32 11 58 18 55 41 12 8 44 13
2 33 17 7 52 20 45 61 25 40 37 48 56 15 34 55 51
14 26 59 51 6 11 36 21 12 13 1 35 36 16 52 28 37
9 53 43 5 32 1 11 2 38 29 3 10 49 31 6 39 60
44 47 43 43 22 36 4 18 54 44 5 15 9 19 37 12 56
11 33 1 38 23 51 11 24 36 17 8 12 2 62 52 59 37
7 34 48 10 16 53 32 36 20 47 30 31 36 28 45 33 47
13 3 51 52 51 51 55 56 14 18 32 11 48 50 1 32 37
38 9 21 33 46 60 39 49 2 50 29 43 12 47 30 50 36
34 19 50 44 41 13 50 31 1 45 37 43 11 48 49 44 1

 
Posted : November 13, 2017 10:53 pm
Jarlve
(@jarlve)
Posts: 2547
Famed Member
 

Interesting ciphers smokie,

Both are quite a bit more cyclic in the 2nd half, probably because of the shortening of the cycle.

Unigram distance is higher for your second cipher (14566) than for your first cipher (13623), probably because of cycles such as, "1 2 3 4 1 2 3 1 2 1 1 2 3 4", where the cycle rule resets and starts decreasing again, so that the 4’s become spread farther apart.

Prime phobia of your 1st cipher is high.

AZdecrypt

 
Posted : November 14, 2017 12:28 pm
Jarlve
(@jarlve)
Posts: 2547
Famed Member
 

Observation: if you throw the 340 into 5 rows (5 by 68, or by fifths), the third row has 2 perfect 7-symbol cycles:

M2clJ5TM2clJ5TM (72)
M2clJ|TM2clJ|TM (72)


d<M+b+ZR2FBcyA64K
-zlUV+^J+Op7<FBy-
U+R/5tE|DYBpbTMKO
2<clRJ|*5T4M.+&BF

AZdecrypt

 
Posted : November 14, 2017 2:57 pm
smokie treats
(@smokie-treats)
Posts: 1626
Noble Member
Topic starter
 

At what period did I encode this remarkable cipher?

[A[Z.Z[A:6O2?.?:
-G-@M,!-6&6!0F,@
4=3O6&60FH%-=31J4
M1Z6::51275:9^K+-
51J]-=H%CL0JGL@K,
0L+K1[0J]L+H/J9KP
^LCH3/KP5+':H='SS
JRZ5SS/RYW)]5P^^X
DW/YW)]WYR<))]%XS
VXP^W*?$C$P@$X)X<
$D$PG$TT"CT;'(^"T
TX(^>R3QQB@Z<B==7
NT;'^N%V_;"G"<_?'
Q_B=N_[<_;'_7;"(N
9N8N7#VVG8Q8GBQ(#
(?IQI9#@8I(9IVV_;
8#4IDEZ#UUE97#UUG
E@BYEY><UIDE<#7#U
U(B_2#DE>B3Y>OIFE
GE@M3!.>,7[UA&%>

15?

 
Posted : November 15, 2017 5:02 am
doranchak
(@doranchak)
Posts: 2614
Member Admin
 

Observation: if you throw the 340 into 5 rows (5 by 68, or by fifths), the third row has 2 perfect 7-symbol cycles:

Interesting… By my count, there are 326 occurrences of 7-symbol cycles. Here are some of the most significant ones:

Here’s the full list: http://zodiackillerciphers.com/combined … ycles.html
I wonder if other pairings line up by rows like that.

Here are the full sequences for your cycles:

http://zodiackillerciphers.com

 
Posted : November 15, 2017 5:49 am
Jarlve
(@jarlve)
Posts: 2547
Famed Member
 

Interesting… By my count, there are 326 occurrences of 7-symbol cycles. Here are some of the most significant ones:

I wonder if other pairings line up by rows like that.

Thank you for checking into that. You are really showing off with that new font. It is neat.

AZdecrypt

 
Posted : November 15, 2017 12:36 pm
Jarlve
(@jarlve)
Posts: 2547
Famed Member
 

At what period did I encode this remarkable cipher?

[A[Z.Z[A:6O2?.?:
-G-@M,!-6&6!0F,@
4=3O6&60FH%-=31J4
M1Z6::51275:9^K+-
51J]-=H%CL0JGL@K,
0L+K1[0J]L+H/J9KP
^LCH3/KP5+':H='SS
JRZ5SS/RYW)]5P^^X
DW/YW)]WYR<))]%XS
VXP^W*?$C$P@$X)X<
$D$PG$TT"CT;'(^"T
TX(^>R3QQB@Z<B==7
NT;'^N%V_;"G"<_?'
Q_B=N_[<_;'_7;"(N
9N8N7#VVG8Q8GBQ(#
(?IQI9#@8I(9IVV_;
8#4IDEZ#UUE97#UUG
E@BYEY><UIDE<#7#U
U(B_2#DE>B3Y>OIFE
GE@M3!.>,7[UA&%>

15?

Period 1: viewtopic.php?f=81&t=3599

AZdecrypt

 
Posted : November 15, 2017 1:42 pm
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