Here’s an interesting encryption method:
It’s basically an incremental Caesar shift that resets at the beginning of each word. I like its simplicity, and how easily it might fool us if we’re not specifically looking for it. Could have easily been done to the Z340 plaintext prior to substitution.
A fellow ACA member told me it is basically an unkeyed, simpler version of the Ragbaby cipher: http://www.dickason.com/caching/OHMIKYragbaby.html
I was looking at Caesars with variants (I think it’s called), but trying to impliment 14 as on the Halloween card as s shift key.
Sorry I am not very clued up on this. 
Here’s an interesting encryption method:
Since every encoded word remains the same from one instance to another – "tig = the" – letter n-grams could be created from encoded text to test it.
Mystery cipher:
Z@(V)PN6#"O!%V;S^ %@IN-(3(SC3T)'N CNG4^4%$YN^SDZ02K I.OM1_M?U*HO?$8S K*$4CDBU@IMB@UWDI :I]Y&8U1K4SN&YBO5 644N9SOO9WN#NFL(> Y5??7!G#:SA+.:/G9 G9#X6WT@<1UJQUIK; 7P7BHBNJ?D?P]I,-O WXS<O#HZU#XF72I@ DUB/LD:"%[E6=)LBO O0N#EN].IDN?L4Y_ _^KJ*;@I'0)>S5R4! SDZR?@2KI1U+O?VSH IZ!;J,Z%QBF/#U3. 'AU@(0$?U>I#=:DO@ NO6"DW*28IPOF@S'[ )F&?N;QVBU9#TS1LD 2<#F%=-;S!MBUJH3O
Mystery cipher:
I only tried it for a quarter of an hour. Unfortunately I don’t have the time at the moment. My (few) tests suggest that a rotation is involved (alternatively "vertical reading direction"). Unfortunately, I’m not further yet. But the cipher behaves in any case very interesting!
This is one of my favorite websites. Klaus Schmeh’s cryptography blog. He is slowly revealing, one by one, the top 50 unsolved cryptograms.
He just put the fourth part of Kryptos at #4, and has also revealed #5 to #50. The Zodiac 340, so far, is not on the list. So it is going to either not be on the list, or in the top 3. If he lists the 340, it will be interesting to read what he has to say about it. I will be watching.
http://scienceblogs.de/klausis-krypto-kolumne/
EDIT: Here is #4 to #50.
I bet z340 is in the top 3. z340 is also at the top of one of his books. A few years ago I made Klaus aware of this forum. Maybe I should send him the links to the doranchak’s videos so he can post them in his future posts.
Just two diagonal transpositions next to each other (underlying plaintext is continuous). The description rectangle was 20×17, the left and right half of which were transposed diagonally. That was transferred in 17×20 and then substituted. I’ve set 25% randomness.
klHxJMs2q+cmAsKBd ksvDAnE3rhiysrzAf kjBOOPeBI+h8ickde v5DFXYj4EkfoTGrpQ 1+XSY2kAhHkZaT5LW q+W0ivrsjlcxBJm5P VWM+hdxqNKe+YOknP wLLzMkt+oR+pbdCDr c0SlTE+UumV+nYxy+ MdkA8eoIz5qtpNfr0 OqZXR8BgCi6D+WQkr +dyvyzdRjHNFTK0Lx GsUaJbEeIV+d5AZd+ lqKsHWBXmayFnAD8o +zMbNQhLi3E6J0PxC rSoRl65ZHSsrkm9Ad SWrcUjfqB+KL7wyr2 V+xt6ucd55f1nfca+ dshA2M+WHaiEJXA30 ++xY9yo+KNz0qLelJ
Hey Largo.
I’ve added this transposition to my solver for the next AZdecrypt release. It has solved your cipher and no results on the 340 so far. It can pick any set of dimensions and then make a horizontal or vertical split at any offset of which each part could have its own transposition (none, mirrored, flipped, columnars, diagonals).
Score: 24485.95 Ioc: 0.06314 Multiplicity: 0.18529 N-grams: 925 PC-cycles: 4588 Split(20*17,V,10,Diagonal(UTP,C:1A),Diagonal(UTP,C:1A)) MANIACMANSIONISAG RAPHICADVENTUREVI DEOGAMEDEVELOPEDA NDPUBLISHEDBYLUCA SFILMGAMESITFOLLO WSTEENAGEPROTAGON ISTDAVEMILLERASHE ATTEMPTSTORESCUEH ISGIRLFRIENDFROMA MADSCIENTISTWHOSE MINDHASBEENENSLAV EDBYASENTIENTMETE ORTHEPLAYERUSESAP OINTANDCLICKINTER FACETOGUIDEDAVEAN DTWOOFHISSIMPLAYA BLEFRIENDSTHROUGH THESCIENTISTSMANS IONWHILESOLVINGPU ZZLESANDAVOIDINGD
This is one of my favorite websites. Klaus Schmeh’s cryptography blog. He is slowly revealing, one by one, the top 50 unsolved cryptograms.
He just put the fourth part of Kryptos at #4, and has also revealed #5 to #50. The Zodiac 340, so far, is not on the list. So it is going to either not be on the list, or in the top 3. If he lists the 340, it will be interesting to read what he has to say about it. I will be watching.
http://scienceblogs.de/klausis-krypto-kolumne/
EDIT: Here is #4 to #50.
The Somerton man code number 5. my take is that it is ship to ship 1930 40 ish two letter (maritime) international code of signals. Signals can be sent by flag hoist, signal lamp ("blinker"), flag semaphore, radiotelegraphy. AB = abandon ship D means negative small c means affirmative ETC..
not really a secret code in my opinion. just written in the heat of the moment (sea battle?) and more legible to the writer although i believe i have worked out most of it IMO. i have worked on it extensively. cheers
Hi Jarlve,
I’ve added this transposition to my solver for the next AZdecrypt release. It has solved your cipher and no results on the 340 so far. It can pick any set of dimensions and then make a horizontal or vertical split at any offset of which each part could have its own transposition (none, mirrored, flipped, columnars, diagonals).
Wow, that’s really cool! Thank you for remembering this transposition idea.
Translated with http://www.DeepL.com/Translator
I’ve added this transposition to my solver for the next AZdecrypt release. It has solved your cipher and no results on the 340 so far. It can pick any set of dimensions and then make a horizontal or vertical split at any offset of which each part could have its own transposition (none, mirrored, flipped, columnars, diagonals).
Jarlve, I am glad you are still working on these ideas. I have been working on a similar idea but it is not ready for prime time yet. Maybe in weeks. I will let you know. Maybe you will like it. I will be back.
Wow, that’s really cool! Thank you for remembering this transposition idea.
It was on my to do list but getting there… Thank you for coming up with it.
Jarlve, I am glad you are still working on these ideas. I have been working on a similar idea but it is not ready for prime time yet. Maybe in weeks. I will let you know. Maybe you will like it. I will be back.
Sure thing smokie.
Mystery cipher:
Z@(V)PN6#"O!%V;S^ %@IN-(3(SC3T)'N CNG4^4%$YN^SDZ02K I.OM1_M?U*HO?$8S K*$4CDBU@IMB@UWDI :I]Y&8U1K4SN&YBO5 644N9SOO9WN#NFL(> Y5??7!G#:SA+.:/G9 G9#X6WT@<1UJQUIK; 7P7BHBNJ?D?P]I,-O WXS<O#HZU#XF72I@ DUB/LD:"%[E6=)LBO O0N#EN].IDN?L4Y_ _^KJ*;@I'0)>S5R4! SDZR?@2KI1U+O?VSH IZ!;J,Z%QBF/#U3. 'AU@(0$?U>I#=:DO@ NO6"DW*28IPOF@S'[ )F&?N;QVBU9#TS1LD 2<#F%=-;S!MBUJH3O
What I did here was an L-route transposition (after homophonic). Something I saw in a manual. Because the transposition happened after sequential homophonic substitution there are some hints here and there.
Example matrix:
1 37 71 103 133 161 187 211 233 253 271 287 301 313 323 331 337 2 38 72 104 134 162 188 212 234 254 272 288 302 314 324 332 338 3 39 73 105 135 163 189 213 235 255 273 289 303 315 325 333 339 4 40 74 106 136 164 190 214 236 256 274 290 304 316 326 334 340 5 41 75 107 137 165 191 215 237 257 275 291 305 317 327 335 336 6 42 76 108 138 166 192 216 238 258 276 292 306 318 328 329 330 7 43 77 109 139 167 193 217 239 259 277 293 307 319 320 321 322 8 44 78 110 140 168 194 218 240 260 278 294 308 309 310 311 312 9 45 79 111 141 169 195 219 241 261 279 295 296 297 298 299 300 10 46 80 112 142 170 196 220 242 262 280 281 282 283 284 285 286 11 47 81 113 143 171 197 221 243 263 264 265 266 267 268 269 270 12 48 82 114 144 172 198 222 244 245 246 247 248 249 250 251 252 13 49 83 115 145 173 199 223 224 225 226 227 228 229 230 231 232 14 50 84 116 146 174 200 201 202 203 204 205 206 207 208 209 210 15 51 85 117 147 175 176 177 178 179 180 181 182 183 184 185 186 16 52 86 118 148 149 150 151 152 153 154 155 156 157 158 159 160 17 53 87 119 120 121 122 123 124 125 126 127 128 129 130 131 132 18 54 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 19 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36
Added the operation to my transposition solver:
Restart: 1 Hill climber: 113/5000 @ 500000 Score: 24518.66 Ioc: 0.06453 Multiplicity: 0.18529 N-grams: 394 PC-cycles: 1248 L-route(17*20,UTP,C:2) ASPOSSIBLYTHECOOL ESTGRANDMAONTHEIN TERNETYOUMAYWELLH AVEALREADYHEARDOF SHIRLEYCURRYSHESA NEIGHTYTWOYEAROLD YOUTUBERWHOPRIMAR ILYRECORDSHERSELF PLAYINGSKYRIMANDH ASPRETTYMUCHWONTH EHEARTSOFEVERYONE INTHEELDERSCROLLS COMMUNITYREFERRIN GTOHERSUBSCRIBERS ASGRANDKIDSSHEGOE SOUTOFHERWAYTOREP LYTOEVERYCOMMENTO NHERVIDEOSANDHERL ETSPLAYSAREBASICA LLYTHEMOSTWHOLESO
The PC-cycles (plain text to cipher text cycle score) is only 1248 as you can see. Because the cipher text was transposed after homophonic as stated earlier. If you then go to Solver options within AZdecrypt and change "(Substitution + transposition) PC-cycles, use untransposed texts" to 0 it then correctly matches the cycles resulting in a much higher PC-cycles score:
Restart: 1 Hill climber: 3/5000 @ 500000 Score: 24518.66 Ioc: 0.06453 Multiplicity: 0.18529 N-grams: 394 PC-cycles: 19634 L-route(17*20,UTP,C:2) ASPOSSIBLYTHECOOL ESTGRANDMAONTHEIN TERNETYOUMAYWELLH AVEALREADYHEARDOF SHIRLEYCURRYSHESA NEIGHTYTWOYEAROLD YOUTUBERWHOPRIMAR ILYRECORDSHERSELF PLAYINGSKYRIMANDH ASPRETTYMUCHWONTH EHEARTSOFEVERYONE INTHEELDERSCROLLS COMMUNITYREFERRIN GTOHERSUBSCRIBERS ASGRANDKIDSSHEGOE SOUTOFHERWAYTOREP LYTOEVERYCOMMENTO NHERVIDEOSANDHERL ETSPLAYSAREBASICA LLYTHEMOSTWHOLESO
Jarlve, I am glad you are still working on these ideas. I have been working on a similar idea but it is not ready for prime time yet. Maybe in weeks. I will let you know. Maybe you will like it. I will be back.
Sure thing smokie.
I messed around with the matrix unfolding idea, but it isn’t working out too well.
The L route idea is really cool. I am still trying to figure out a route that does P19 and pivots.
I have a new encoder spreadsheet. I can designate and it will use exactly the number of symbols that I tell it to. No more approximations. Diffusion is very precise, and I can also very precisely modify the efficiency of the key. I can designate one symbol as a poly, or a 1:1, and set a target symbol count, and it will come as close as possible. I can set default any isometric cycle pattern that I want for any size homophone group. Make perfect cycles, all random, randomization by area, and even random except no repeat the last symbol. And combinations of the above for any letter of the alphabet, and make different letters act differently. I am using it now to try to find a good model for 26 L=2 and similar AB cycles.
Smokie treats –
viewtopic.php?f=81&t=907&p=69052#p68412
Can you lock specific positions to a specific letter, e.g.
‘IGIVETHEM , Z340#9 ‘I’ locked to be its plaintext ‘I’ (i.e. no action will be
taken on a specific position where [it is believed] no decipherment step is necessary for that position).
