Idea/scope of thread: the Z340 may not be solvable as a whole but it may contain a part or parts (sub strings) that are solvable. For example, Olson considered lines 1, 2, 3, 11, 12 and 13 to contain a solution plain text somehow.
To start work in this direction I extracted all continuous sub strings of the Z340 with a multiplicity 0.3 to 0.35. I first did the same with the Z408 to have a control. With AZdecrypt’s Batch substitution it is possible to measure the accuracy of the solution given that the plain text is known:
cipher_information=1-149_348 9%P/Z/UB%kOR=pX=B WV+eGYF69HP@K!qYe MJY^UIk7qTtNQYD5) S(/9#BPORAU%fRlqE k^LMZJdrpFHVWe8Y @+qGD9KI)6qX85zS( RNtIYElO8qGBTQS#B Ld/P#B@XqEHMU^RRk cZKqpI)Wq!85L solution_plaintext= ILIKEKILLINGPEOPL EBECAUSEITISSOMUC HFUNITIAMOREFUNTH ANKILLINGWILDGAME INTHEFORRESTBECAU SEMANISTHEMOATDAN GERTUEANAMALOFALL TOKILLSOMETHINGGI VESMETHEMOATT
Excluding the last 18 characters of the Z408 there are 6104 sub strings with a multiplicity of 0.3 to 0.35 (very redundant). I now needed to know how many iterations and restarts to consider for the test to get a really high average solve accuracy for the Z408 sub strings. So I ran multiple tests at increasing number of iterations:
500,000 iterations: 21.37% of ciphers solved with accuracy >= 70%
1,000,000 iterations: 33.60% …
2,000,000 iterations: 51.09% …
4,000,000 iterations: 67.59% …
8,000,000 iterations: 81.70% …
16,000,000 iterations: 91.30% …
32,000,000 iterations: 97.00% …
64,000,000 iterations: 99.18% …
128,000,000 iterations: 99.75% …
128,000,000 iterations with 10 restarts: 100% !!!
Takeaway is that AZdecrypt was able to achieve a 100% solve rate on the Z408 sub string ciphers using 6-grams but it took almost 2 days.
And now I could proceed to the Z340 sub strings with nearly 100% confidence in the results. There are 5621 Z340 subs strings with multiplicity 0.3 to 0.35.
And for the results. The highest AZdecrypt score of the Z340 sub strings is 22909.94 while the lowest score of the Z408 is 23528.00. So that does not look good to start with.
The best result:
Score: 22909.94 IOC: 0.0640 Multiplicity: 0.3496 Hours: 14.59 Repeats: THEREI STHE OTHE OTH EAR DIS PLE WAS EAN IGH AST AN PT-to-CT cycles: 117 63-225_349 LIINDOTHEISPLEAST BIGHUGEANDTALINEB UTFORYESIDISCOVER CONSTAYCOMPLELITW ASINTHEREISIMNOTH EROTHDISAVOIDMILE ARTHRIVINGSPEARAH ESWEDLOREANMANSWH ENIGHTSTHEREIWAST HEYCANACTW
And this result almost has a full BECAUSE repeat:
Score: 22488.64 IOC: 0.0631 Multiplicity: 0.3442 Minutes: 26.47 Repeats: BECAUS THIS (2) ETTH STOR RES EVE ORE ORM ER IN OM PT-to-CT cycles: 225 3-185_344 APTORMBUILDYOULIT ESTORINAGAINTHIST HEVERCOATIDONTGET THROWNMYTREEATUSE VENAFLIMSBECAUSTW ARSORONLYUSPUNTOM ETHISURESOMANDITO UGHFORESIGNEDDELI VEBECAUSSETTHATON ORMERGERTHISSTORE ASMAKINGSTBYV
Conclusion: the Z340 does not contain any solvable multiplicity 0.3 to 0.35 continuous sub string on par with the Z408.
Further work would be to try multiplicity ranges 0.35 to 0.4 and 0.4 to 0.45 etc.
LIINDOT HE IS PLEAST BIG HUGE AND TALINE B
UT FOR YES I DISCOVER CON STAY COMPLELI T W
AS IN THERE IS IM NOT HER OTHD IS AVOID MILE
AR THRIVING SPEAR A HES WED LOREAN MANS WH
E NIGHT ST HERE I WAS THEY CAN ACT W
A PTORM BUILD YOU LITE STOR IN AGAIN THIS T
HEVER COAT I DONT GET THROWN MY TREEAT U SE
VEN AFLIMS BECAUST WARS OR ONLY US PUN TO M
E THI SURE SO MAN DITOUGH FO RESIGNED DE LI
VE BECAUS SET THAT ONOR MERGER THIS STORE
AS MAKING STBYV
that sounds extremely interesting and shows again how powerful AZDecrypt is. Currently I’m taking a little timeout from z340, but I do have one question: Do you think it makes sense to repeat this test for some of the special bigram peak ciphers? So P19, Mirror P15, Horizontal Shift + P19 and 48/8 phenomenon?
There are 5621 Z340 subs strings with multiplicity 0.3 to 0.35.
Has it ever been determined how many substrings of the above mentioned ciphers have such multiplicity?
Translated with http://www.DeepL.com/Translator (free version)
Do you think it makes sense to repeat this test for some of the special bigram peak ciphers? So P19, Mirror P15, Horizontal Shift + P19 and 48/8 phenomenon?
I thought of this as well and I am pondering it.
Has it ever been determined how many substrings of the above mentioned ciphers have such multiplicity?
It is probably similar.