This is just a test to see if Jarlve (or anyone) can solve. It’s similar to Beale cipher #3
It should be solvable, I think. Any mistakes are mine. It was hard to format it so it lined up.
24 10 78 41 27 11 55 72 105 88 101 9 51 47 108 24 55 56 76 61 103 59 105 10 38 74 118 98 21 46 79 115 117 61 113 15 56 106 89 41 79 53 118 122 92 111 106 67 35 58 96 43 29 72 43 25 36 117 90 114 65 34 117 44 80 5 105 41 120 70 78 38 105 108 91 118 58 31 92 100 74 44 123 92 19 2 7 101 80 62 108 112 79 89 89 93 73 68 55 38 59 45 34 50 41 117 53 114 9 39 104 121 24 109 100 88 96 116 97 85 117 65 37 72 29 92 74 25 46 49 24 115 49 87 79 53 118 9 120 77 68 65 46 63 120 50 118 36 116 54 43 72 68 97 1 79 111 116 6 70 52 53 99 89 119 25 52 59 27 94 66 2 88 8 33 26 74 17 83 92 67 35 123 112 29 79 1 30 121 22 103 92 29 96 87 44 95 42 24 47 22 66 81 106 42 104 63 74 97 116 21 59 85 80 121 22 21 62 20 14 121 28 63 19 85 9 83 36 8 40 8 67 73 76 65 122 61 84 43 94 35 105 79 91 51 38 119 20 61 30 8 52 26 115 11 90 54 50 44 45 46 15 24 115 54 73 13 53 118 105 36 13 114 83 5 54 38 36 104 9 108 61 103 81 51 42 9 59 44 82 56 41 60 14 57 122 74 84 91 118 49 57 11 64 54 55 28 69 43 91 16 80 121 22 81 68 19 38 37 53 55 58 4 79 38 20 78 47 112 110 72 111 2 53 92 98 85 8 88 59 71 50 113 121 21 47 68 64 123 32 94 87 11 72 89 14 39 52 51 19 56 2 34 104 62 73 123 90 107 105 41 13 53 44 123 36 34 16 106 68 55 108 73 84 77 99 100 94 88 29 72 71 57 99 3 23 121 80 52 8 31 99 27 123 86 49 110 120 122 99 27 122 65 25 34 50 87 103 109 65 2 62 57 26 97 88 11 52 49 86 58 7 51 65 9 18 71 87 11 66 52 113 75 114 17 84 118 121 86 2 88 40 94 67 67 93 21 109 66 17 2 77 8 111 33 92 3 40 62 22 110 35 93 85 81 93 72 72 70 36 40 94 19 85 106 62 81 2 76 39 70 61 83 20 67 103 36 110 7 22 123 120 111 103 7 99 118 30 64 95 85 17 11 73 42 34 25 7 40 107 82 74 28 44 78 18 97 13 34 109 83 120 50 58 88 99 27 3 52 53 34 14 96 43 21 92 4 58 100 12 78 18 74 37 7 9 102 120 3 46 94 96 66 14 47 73 72 24 120 42 97 30 108 119 94 101 26 63 102 60 45 40 71 85 72 49 123 40 11 60 1 105 39 16 24 115 72 24 48 19 9 77 20 30 26 62 101
-glurk
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I don’t believe in monsters.
Ok, I’ll bite. 🙂
ASACHALLENGEANDALSOTOTESTTHEABILITIESOFCIPHERSOLVINGALGORITHMSIHAVECREATEDTHISRATHERLONGANDDIFFICULTTESTCIPHERINAMANNERSIMILARTOBEALECIPHERNUMBERTHREEGLURKISEXEMPTFROMTHISONEBUTJARLVEDAIKONDORANCHAKANDSMOKIETREATSANDANYONEELSEAREWELCOMETOGIVEITATRYTOEMULATETHEBEALECIPHERIHAVETRIEDTOMAKETHISCLOSETOTHESAMELENGTHANDMULTIPLICITYANDALSOPRESENTITINANUMERICALFORMALSOSINCETHECIPHERSHOULDCONTAINALISTOFNAMESTHESEARETHEMOSTCOMMONSURNAMESINAMERICASMITHJOHNSONWILLIAMSJONESBROWNDAVISMILLERWILSONMOORETAYLORANDERSONTHOMASJACKSONWHITEHARRISMARTINTHOMPSONGARCIAMARTINESROBINSONCLARKRODRIGUESLEWISLEEWALKERHALLALLENYOUNG
It was actually a fairly simple cipher, took only 1 restart. The hardest part was reworking my solver to accept 123 unique symbols, as there are not that many printable ASCII characters.
I TOTALLY screwed up on this. I guess I keep bad notes, I assigned the number of homophones based on the count of unique numbers instead of the count of distinct numbers. Moral of the story for me is keep better notes and don’t make ciphers when tired.
And double-check my own work, LOL.
I’ll do another (correctly!) soon. Sorry about that.
-glurk
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I don’t believe in monsters.
Here’s the new one. This time, it should be 618 characters, with 264 distincts, and the same multiplicity as the Beale three.
Also, the bulk of it is a list of names, just as Beale three was claimed to be. This should be MUCH harder.
85 20 184 6 242 28 206 25 100 253 75 172 48 176 75 173 114 215 16 230 172 31 124 24 158 164 61 210 98 250 183 158 86 123 27 234 68 40 172 260 35 221 258 61 66 153 117 80 176 166 132 263 93 43 73 140 53 188 245 58 131 18 149 56 78 132 102 63 118 188 74 62 116 2 85 10 222 142 15 38 164 161 52 3 202 203 71 167 220 145 4 227 259 227 158 247 157 82 4 17 225 254 37 236 186 61 249 999 55 222 104 221 68 91 248 12 140 23 35 146 150 155 224 58 228 128 82 86 251 170 114 124 50 11 231 139 164 27 64 7 47 104 208 64 48 172 19 72 184 241 169 31 29 147 209 28 22 60 248 186 39 58 37 51 83 210 224 93 107 229 263 104 32 177 103 44 233 226 80 173 113 214 66 44 26 224 245 5 73 257 211 49 115 159 22 157 154 112 16 217 243 197 216 46 36 234 148 13 154 63 152 221 224 132 65 22 182 182 9 78 261 116 174 110 90 179 999 131 23 70 174 105 19 188 256 114 9 76 99 221 136 60 205 59 219 19 248 179 129 97 89 31 250 242 138 52 123 250 168 249 26 187 78 26 173 66 122 162 8 250 163 228 116 69 134 246 208 200 191 117 111 111 92 66 189 127 92 190 98 45 232 245 115 213 184 93 255 134 77 68 111 47 78 203 38 174 119 110 223 136 232 95 139 60 183 183 180 201 111 55 128 211 30 230 4 213 140 23 110 183 225 170 114 66 257 200 101 86 144 160 62 81 244 73 70 156 21 39 56 250 116 92 194 153 55 55 137 47 43 200 194 47 78 94 173 123 37 252 151 106 21 175 213 238 115 24 177 225 162 85 92 177 31 112 194 193 47 61 241 56 4 6 37 247 50 159 9 231 100 234 196 96 262 104 61 108 153 204 233 192 60 62 132 184 20 46 262 58 246 224 237 94 107 151 14 18 207 33 168 201 180 87 136 147 116 11 246 226 91 99 126 86 29 165 130 107 157 211 86 2 252 84 218 183 127 189 171 85 227 100 98 93 48 7 196 92 125 236 63 135 236 66 199 252 166 155 133 3 61 143 118 156 141 215 230 14 249 179 84 195 186 156 45 164 158 205 108 221 55 79 148 99 239 202 55 231 232 230 131 150 999 40 107 249 104 177 202 162 175 98 46 254 107 206 106 264 74 70 100 25 42 249 236 232 114 125 165 115 131 51 9 61 210 70 240 247 133 25 68 117 252 56 9 160 122 229 250 177 41 4 2 82 4 207 67 119 54 238 197 151 172 57 121 999 133 210 44 82 235 73 25 75 239 83 45 63 105 6 154 233 124 127 164 128 261 161 195 129 240 39 212 236 125 120 93 68 47 168 176 220 26 97 86 112 157 185 208 31
-glurk
EDIT: For every "1" in this cipher, I replaced it with "999" I could have used any other number, but I used 999.
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I don’t believe in monsters.
I have to apologize publicly to Jarlve. I thought his program was messing up on my cipher, when it was myself messing it up. 
That said, I still think this one is going to be a difficult solve, and I wish everyone the best. I think this one might be hard, but I keep getting surprised.
It really is (mostly) a list of names, and that should be difficult for an n-gram based solver. I hope. Maybe.
-glurk
EDIT: "won’t be fooled again" might be a hint. or clue. or not.
EDIT 2: The first person that solves this will get a Rubik’s Cube mailed to them, from me, for free!! Prizes! LOL.
EDIT 3: I will need a perfect solution, though. There are NO misspellings in the plaintext 
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I don’t believe in monsters.
Thanks, but unnecessary.
I’m going to make (a serious) attempt at cracking it without cribbing. Could take a couple of weeks.
Thanks, but unnecessary.
I’m going to make (a serious) attempt at cracking it without cribbing. Could take a couple of weeks.
I gave too many hints already, LOL.
And I LIKE my Rubik’s cube. I have it JUST the way I want it. I doubt you will win, AH-HAH-HAH-HA!
-glurk
EDIT: No time limit here. The first person to solve this wins my perfectly lubricated Rubik’s Cube. I only do this "smart-ass" snarky routine because I want to see the solvers improve. And I like to try to be funny. I WILL keep my word, though. Of course I will!
EDIT 2: This is open to everyone. I think this one is going to be hard to solve, but I’ve been wrong before.
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I don’t believe in monsters.
I’m going to give a hint here. The first letter of the cipher is "H"
-glurk
(I probably should not give hints. I am making it too easy.)
EDIT: Some people have stated that Beale #3 is too short to contain a list of names, but I list 35 of them. Just saying.
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I don’t believe in monsters.
I might have to officially give up. Know when to hold ’em, know when to fold ’em, as they say. 🙂 I don’t think I’ll be able to solve it without hints, and with hints that would be a bit like cheating. The main reasons I couldn’t crack it is its high multiplicity combined with the fact that it’s mostly a list of names. Even if you didn’t use really rare names, they will likely be under-represented in the N-grams corpus (i.e. won’t appear very many times), and combined with high multiplicity, which translates to a high degree of freedom of which letters go where, the solver will much likely try to plug common words instead of proper names, and will not get the correct solution. The fact that you have 264 unique symbols in the cipher didn’t help either. A byte (8 bits) can only hold 256 values, so I would have to rework my solver to handle 16-bit values to be able to process more than 256 uniques. Which shouldn’t be too hard, but it will take some time, and I would have to maintain 2 separate versions, as working with 16-bits is slower (probably not by much, but still). So it’ll be a special case version just for this cipher, as I would keep using the faster 8-bit version for most ciphers. So instead, I combined 8 pairs of symbols that only appear once in this ciphers, to be the same symbol for each pair, to bring the number of uniques down to 8-bit territory (264-8=256). Which is like introducing 8 typos in the plaintext, so it didn’t help either. The end result is that I ran my solver for about 14 hours since yesterday, and it didn’t get to anything readable. Maybe it was able to recover small fragments of the plaintext, but being a list of names, I’m just not recognizing it as plaintext. So I’m here to admit that you definitely fooled me, well done! 🙂
Yeah, it’s probably unsolvable, but you never know. ZKDecrypto also uses single bytes, so it can’t handle this one either. I just thought a really difficult challenge would be interesting, since you guys seem to be solving everything else.
I don’t really want to give hints, but I will at least say that all of the names given are "related" in a way, so if someone gets one or two of them, and sees what I was going for, they could probably work out the rest. Maybe. It’s not JUST names either, there is some regular text in there also.
I’ll eventually give the solution at some future time, since that might even be of help too.
-glurk
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I don’t believe in monsters.
